The angle of elevation of the top of a tower as observed from a point in a horizontal plane through the foot of the tower is 32°. When the observer moves towards the tower a distance of 100 m, he finds the angle of elevation of the top to be 63°. Find the heights of the tower and distance of first position from the tower. (Take tan 32°=0.6248 and
tan 63° = 1.9626]
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the height of the Tower is 91.66m and the desires distance is 146.7m
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578 is the correct answer ❤️mark as brainliest
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