Question

The angle of elevation of the top of a tower at
a distance of 120m from its foot on a horizontal
plane is found to be 45°. Find the height of the
tower.​

Answer 1

Step-by-step explanation:

Let AB is the tower of height h meter and AC is flagstaff of height x meter.

∠APB=45 °

and ∠BPC=60 °

tan60° = 120/x+h

3 = 120x+h

x=120 3 −h

tan45° = 120/h

1= 120/h

h = 120

Substitute the value of h in x,

x=120 3 −120

x=120( √3 −1)

x=120(1.73−1)

x=87.6m

Therefore the height of the flagstaff = 87.6m