Question

the angle of elevation of the top of a tower at a point 120m from its base is 45° how much higher should it be raised so that the elevation at the same point may become 60°

Answer 1

Answer:

Step-by-step explanation:

Answer 2

B C =height of tower

C D =Height of flag

IN TRAINGLE A B C
tan 45 degree=
$= bc \\ ab$
1=bc
120

B C=120


Also ,IN TRAINGLE A B D


tan 60 degree=B D
A B


$\sqrt{3} = bd \\ 120$
B D =120 under root 3

so,height of flag =B D -B C
120 Under root -120

=120 (under root 3 - 1)

=120× 0.732

= 87 .84 m