Question

The angle of elevation of the top of a tower at a point on ground 50m away from the foot of tower is 60 degree find height of tower

Answer 1

Heres your answer.. ..

Answer 2

The height of tower is 86.6 m

Step-by-step explanation:

Distance between the point and the foot of tower = Base = 50 m

Angle of elevation = 60°

We are supposed to find the height of tower i.e. Perpendicular

So,$Tan \theta = \frac{Perpendicular}{Base}$

$Tan 60^{\circ}=\frac{Height}{50}$

$\sqrt{3} \times 50 = Height$

86.6 =Height

Hence The height of tower is 86.6 m

#Learn more:

The angle of the elevation of the top of the tower from a 60 metre from its foot is 30 degrees find the height of the tower ​

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