The angle of elevation of the top of a tower from a certain point is 30. If the observer moves 40 m towards the tower, the angle of elevation of the top of the tower increases by 15. The height of the tower is:
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Answer:29.282 meter
Step-by-step explanation:
Let us assume that person is x mt from tower and height of tower is y mt so angle of elevation us 30° so tan 30 = y/x on solving y= .577x if move 40 Mt toward tower then tan (30+15) = tan 45 = y/x-40 , y =x-40 from both equation we get y =29.282 mt
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Let AB be the tower of height h metres, C and D be the two points of observation.Then,
From right ∆ABD,we have
From right ∆ABC, we have
Hence, the height of the tower is 10(√3+1)m.
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