the angle of elevation of the top of a tower from a point situated at 100m far from the foot of tower is 30 degree. find the height of the tower
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So let's AB=tower =100m
BC =the distance between the the point and the base of tower =?
in ΔABC
Using Tan ratio
Tan Φ=opp÷abj
Tan 30=AB÷BC
1÷√3=100÷BC
BC=100√3m
BC =the distance between the the point and the base of tower =?
in ΔABC
Using Tan ratio
Tan Φ=opp÷abj
Tan 30=AB÷BC
1÷√3=100÷BC
BC=100√3m
vinayak19:
sorry by mistake
it will come 100/root3
sorry by mistake
ok
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