The angle of elevation of the top of a tower from a point onthe ground which is 30 m away from the foot of the tower is 30°. Find the height of the tower
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Tan30'=o/a
1/√3=AB/BC
1/√3=AB/30
√3AB=30
AB=30/√3
AB=10×3/√3
AB=√3×√3×10/√3
therefore,AB=10√3
1/√3=AB/BC
1/√3=AB/30
√3AB=30
AB=30/√3
AB=10×3/√3
AB=√3×√3×10/√3
therefore,AB=10√3
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OK bro that's is the answer of your question
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hemanthheman25:
u welcome bro
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