Question

The angle of elevation of the top of a tower from a point A due south of the tower is α and from B due east of tower is β. If AB = d, show that the height of the tower is d/ √ cot 2 α+ cot2β

Answer 1

Hope these help.....

Answer 2

Thank you for asking this question. Here is your answer:

We will let ∠CAD = θ

∠CBD = 90° - θ

In ΔCDA,  CD/AD = tan θ

CD /a m = tan θ --- (1)

In ΔCDB, CD/BD = tan (90° - θ)

CD / bm = cot θ

CD/ bm = 1/ tan θ

CD / bm = am/ CD

CD² = ab m²

CD = √ab m

So the height of the tower is √ab m

If there is any confusion please leave a comment below.