Question

The angle of elevation of the top of a tower from a point at a distance of 100m from the base of the tower is found to be 45°. The height of the tower is​

Answer 1

Answer :

Height of tower = 100 m

Solution :

Given,

Angle of elevation = 45°

Distance from foot of tower to the observer = 100 m

tan θ = opp/adj

tan 45° = h/100

1 = h/100

h = 100

Therefore,

Height of the tower = 100 m

Answer 2

The angle of elevation of the top of a tower from a point at a distance of 100m from the base of the tower is found to be 45°. The height of the tower is 100m