Math, asked by vasu4704, 11 months ago

The Angle Of Elevation Of The Top Of A Tower From A Point On The Ground Which Is 15M Away From The Foot Of The Tower Is 60 Degree The Height Of The Tower Is

Answers

Answered by ChiKesselman
2

Answer:

Height of the tower = 25.98m

Step-by-step explanation:

Let height of the tower be "x"

From 15m away, angle of elevation of the top of a tower = 60 degree

So, we can say that:

Base = 15m

Angle of elevation "Ф"  = 60°

Using TanФ = Height / Base

Tan 60° = x / 15

√3 = x / 15

x = 15√3

Using √3 = 1.732

x = 1.732 × 15

x = 25.98 m

Therefore height of the tower is 25.98m.

Attachments:
Similar questions