The Angle Of Elevation Of The Top Of A Tower From A Point On The Ground Which Is 15M Away From The Foot Of The Tower Is 60 Degree The Height Of The Tower Is
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Answer:
Height of the tower = 25.98m
Step-by-step explanation:
Let height of the tower be "x"
From 15m away, angle of elevation of the top of a tower = 60 degree
So, we can say that:
Base = 15m
Angle of elevation "Ф" = 60°
Using TanФ = Height / Base
Tan 60° = x / 15
√3 = x / 15
x = 15√3
Using √3 = 1.732
x = 1.732 × 15
x = 25.98 m
Therefore height of the tower is 25.98m.
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