Question

The angle of elevation of the top of a tower from
a point on the ground, which is 30 m away from
the foot of a tower of height 10 √3 m is​

Answer 1

Step-by-step explanation:

let angle ABC= thita

Therefore, Tan thita= 10√3/30/√3

Tan thita= 1/√3

Tan thita=Tan30

Therefore, thita= 30

Therefore, angle ABC= 30.