Question

The angle of elevation of the top of a tower from a point on the ground which is
30m away from the foot of the tower is 30", the height of tower is
​

Answer 1

Given :

• The angle of elevation of the top of a tower from a point on the ground which is 30m away from the foot of the tower is 30

To find :

• the height of tower

Solution :

Let AB be the tower and C be a point on the ground such that BC = 30 m. Also let AB = h ms

the angle of elevation of the top A form C is 30°

so,

in right angled ΔABC

AB/BC = tan 30°

h/30 = 1/√3

h = 30/√3

h = 10√3

h = 10 × 1.732

h = 17.32

the height of tower is 17.32

Answer 2

Answer:

Given the tower is 30m away from point A.

Given angle of elevation of top of tower is 30.

Let the height of tower be x

tan30=

AB

BC

=

3

1

=

30

x

x=

3

30

⋅

3

3

=

3

30×

3

=10

3

∴ Height of tower =10

3

=10×1.732

=17.32m.