The angle of elevation of the top of a tower from a point on the ground, which is 20m away from
the foot of the tower is 60'. Find the height of the tower.
(a) 105 m
(b) 30 5 m
(c) 20/3 m (d) none of these
Answers
Answered by
3
Step-by-step explanation:
In ΔADC
tan30
o
=
AC
DC
3
1
=
d
h
........(1)
d=
3
h
→d=
3
×10
3
=30m
In ΔBCD
tan60
o
=
BC
DC
3
=
d−20
h
.......(2)
on solving equation (1) & (2)
3
=
3
h−20
h
⇒3h−20
3
=h
2h=20
3
h=10
3
m
height of tower.
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