the angle of elevation of the top of a tower from a point on ground 45 degree on walking 30 meters towards the tower the angle of elevation becomes 60 degree find the height of the tower and the original distance from the foot of the tower
Answers
Answer:
In ΔADC
tan30
o
=
AC
DC
3
1
=
d
h
........(1)
d=
3
h
→d=
3
×10
3
=30m
In ΔBCD
tan60
o
=
BC
DC
3
=
d−20
h
.......(2)
on solving equation (1) & (2)
3
=
3
h−20
h
⇒3h−20
3
=h
2h=20
3
h=10
3
m
height of tower.
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