The angle of elevation of the top of a tower from a point on the ground, which is 30 m away from the foot of the tower, is 30°. Find the height of the tower
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1
Given the tower is 30m away from point A.
Given angle of elevation of top of tower is 30.
Let the height of tower be x
tan30= ABBC
1
=
30
x
x=
3
30
⋅
3
3
=
3
30×
3
=10
3
∴ Height of tower =10
3
=10×1.732
=17.32m.
Answered by
3
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