The angle of elevation of the top of a tower from a point on the ground, which is 30 m away from the foot of the tower, is 30°. Find the height of the tower
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Answer:
10√3 m
Explanation:
Assume that triangle be ABC where AB is height of the tower and BC is 30 m away from the foot of the tower.
Also, /_C = 30° and /_B = 90°
We need to find out the height of the tower i.e. AB
In ∆ABC
tanC = AB/BC
tan 30° = AB/BC
1/√3 = AB/30
AB = 30/√3
Multiply and divide by √3
AB = 30/√3 × √3/√3
AB = 30√3/3
AB = 10√3
Therefore, the height of the tower is 10√3 m.
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