The angle of elevation of the top of a tower from a point on the ground, which is 30 m away from the foot of the tower, is 60°. find the height of the tower (take √3 = 1.732)
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Answer:
distance from the ground to foot of tower= 30 m
angle of elevation=60 degrees.
tan∅=perpendicular/base
tan 60°= height of tower/30 meters
√3 = height/30
height= 30 x √3 =30 x 1.732 = 51.96 meters
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