Question

The angle of elevation of the top of a tower from a point on the ground, which is 30 m
away from the foot of the tower, is 30°. Find the height of the tower.
A kite is flying at a height of 60 m above the ground. The string attached to the kite is​

Answer 1

Answer:

$tan30^{o} = \frac{h}{30}$

$h = \frac{30}{\sqrt{3} }$

$h = 10\sqrt{3}$

Therefore Height of Tower is 10√3

Answer to The Kite :

AB = 60 m

segment AC represents the length of the string

m ∠ ACB = 60º

In right angled ∆ ABC,

sin 600 = side opposite to 600/Hypotenuse

∴ sin 600 = AB/AC

∴ √3/2 = 60/AC

∴ AC = 120/√3

∴ AC = (120/√3)× (√3/√3)

∴ AC = 40√3 m

∴ AC = 40 × 1.73

∴  AC = 69.2 m