Question

The angle of elevation of the top of a tower from a point on the ground, which is 40 m

away from the foot of tower is 60o

, Find the height of the tower.​

Answer 1

Step-by-step explanation:

tan 60° = p/b = tower height / distance from foot

√3 = height/ 40m

height = 40√3 m

hope this will help you

mark this answer as brainlist

Answer 2

$\huge \bold\color{lime}\maltese \color{orange}A \color{red}n \color{green}s \color{blue}w \color {purple}e \color {cyan}r$

$\large{ \underline{\underline{Given}}}$

• The angle of elevation from a point on the ground to the top of the tower is 60°.
• The distance between the point on the ground and the tower is 40m.

$\large{ \underline{\underline{To \: find}}}$

• The height of the tower

$\large{ \underline{\underline{Solution}}}$

Refer the attachment for diagram

We want to find the height of the tower(BC) which is opposite to the angle of elevation.

The distance between the point on the ground and the tower is adjacent to the angle of elevation.

$\therefore \: we \: use \: tan \: \theta = \frac{opposite}{adjacent}$

$In \: ∆ ABC$

$tan \: 60 \degree = \frac{BC }{AC}$

$WKT, tan \: 60° = \sqrt{ 3}$

$\frac{ \sqrt{3} }{1} = \frac{BC }{40}$

While cross-mulplying we get,

$BC = 40 \sqrt{3} \: m$

$\implies \: the \: height \: of \: the \: tower \: is \: 40 \sqrt{3}\: m$