the angle of elevation of the top of a tower from a point on the ground which is 20cm away from the foot of the tower is 45 . Find the height of the tower
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Answer:
Let the distance between point of observation and foot of tower BC=20m
Height of tower AB=H
Angle of elevation of top of tower θ=60
0
Now from figure ΔABC
We know that, ΔABC is a right angle triangle.
tanθ=
BC
AB
tan60
0
=
20
h
⇒
20
h
=
3
⇒h=20
3
m.
Therefore, height of tower=20
3
m
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