Question

The angle of elevation of the top of a tower from a point on the ground, which is 64 m away from the foot of the tower is 45°. The height of the tower is

Answer 1

Answer:

Correct option is

C

30

REF.Image.

30m away / 45∘ inclination.

Let the height of tower be h m

so AB=hm

Distance of the point from

foot of tower = 30m 

CB=30m

Angle of elevation =45∘

∠ACB=45∘

Since tower is vertical to ground

∠ABC=90∘

Now tanC=sideadjacenttoangleCsideopptoangleC

tanC=CBAB

tan45=CBAB

1=30H

H=30

Hence height of tower = 30m

Answer = option C=30m

Step-by-step explanation:

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