Question

The angle of elevation of the top of a tower from a point on the ground, which is 30 m away from the foot of the tower, is 30°. Find the height of the tower.​

Answer 1

17.320 m

Step-by-step explanation:

Refer the attached figure

AB = Height of tower

BC = 30 m

∠ACB = 30°

InΔABC

Tan \theta=\frac{Perpendicular}{Base}Tanθ=BasePerpendicular

Tan30^{\circ}=\frac{AB}{BC}Tan30∘=BCAB

30 \times \frac{1}{\sqrt{3}}=AB30×31=AB

17.320=AB17.320=AB

Hence The height of tower is 17.320 m

Answer 2

$\huge\mathbb\fcolorbox{purple}{Green}{☆AnSwER♡}$

Let AB be the tower of height h metres and let C be a point at a distance of 30 m from the foot of the tower. The angle of elevation of the top of the tower from point C is given as 30º.

• ʜ/ 30 = 1 / √3

ᴜꜱɪɴɢ ᴛʜᴇ ꜰᴏʀᴍᴜʟᴀ ᴏꜰ ᴛᴀɴ 30°

ʜ= 10√3 ᴍ

[ʜᴇɴᴄᴇ ʜᴇɪɢʜᴛ ᴏꜰ ᴛʜᴇ ᴛᴏᴡᴇʀ ɪꜱ 10√3 ᴍᴇᴛʀᴇꜱ].