Question

The angle of elevation of the top of a tower from a point on the ground that is away from the foot of the
tower is 45 Degrees. Find the height of the tower

Answer 1

Given:

The angle of elevation of the top of a tower from a point on the ground that is 30m away from the foot of the  tower is 45 Degrees.

To Find:

Find the height of the tower

Solution:

It is given that the angle of elevation of the top of a tower from a point 30m away is 45 degrees, let the height of the tower be x,

We can form a right angle triangle from the following case in which the perpendicular will be the height of the tower which is x and the base will be the distance of the tower and the point which is 30m and angle theta is 45 degrees,

now we can use simple trigonometry that is,

$tan\theta =\frac{p}{b}\\tan45=\frac{x}{30}\\\frac{x}{30} =1 \\x=30$

So the height of the tower will also be equal to 30m as the value of tan 45 is 1.

Hence, the height of the tower is 30m.

Right Question:

The angle of elevation of the top of a tower from a point on the ground that is 30m away from the foot of the  tower is 45 Degrees. Find the height of the tower