Question

the angle of elevation of the top of a tower from a point on the ground, which is 30m away from the foot of the tower is 30 digree. find the height of the tower

Answer 1

distance between the point and the foot of the tower =30m
angle of elevation =30°
then height of the tower =tan 30°=P/B
P/30=1/√3=30√3/3

Answer 2

Answer:

17.320 m

Step-by-step explanation:

Refer the attached figure

AB = Height of tower

BC = 30 m

∠ACB = 30°

InΔABC

$Tan \theta=\frac{Perpendicular}{Base}$

$Tan30^{\circ}=\frac{AB}{BC}$

$30 \times \frac{1}{\sqrt{3}} = AB$

17.320 = AB

Hence The height of tower is 17.320 m