the angle of elevation of the top of a tower from a point on the ground,which is 30m away from the foot of the tower is 45 degree. the height of the tower is what(in metres)?
Answers
Answered by
1
sin 45=1/under root2
AB/AC= AB/45
45=AB×under root2
AB=45under root 2
AB/AC= AB/45
45=AB×under root2
AB=45under root 2
violeena20:
thank u sooo much
wlcm g
Similar questions