The angle of elevation of the top of a tower from a point on the ground is 30 . On walking 100m towards the tower the angle of elevation changes to 60 . Find the height of the tower
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let,AB as h
BC as x
then BD is 100+x
tan 60°= AB/BC
root3 =h/x
h=50×root 3 ...(1)
tan30=AB/BD
1/root3=h/100+x
100+x=h×root3
100+x=root3×x×root3 (from1)
100+x=3x
100=3x-x
100=2x
x=50
h=root3×x
h=root3×50
hope this will help u❤❤
BC as x
then BD is 100+x
tan 60°= AB/BC
root3 =h/x
h=50×root 3 ...(1)
tan30=AB/BD
1/root3=h/100+x
100+x=h×root3
100+x=root3×x×root3 (from1)
100+x=3x
100=3x-x
100=2x
x=50
h=root3×x
h=root3×50
hope this will help u❤❤
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here is your answer
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