The angle of elevation of the top of a tower from a point on ground which is 30 mtrs away from the foot of tower is 30° hight of the tower
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Height of the tower is shown above....
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Step-by-step explanation:
In ∆ ABC,
tan ∅ = Perpendicular/Height
tan 30° = AB/BC
1/√3 = AB/30
30/√3 = AB
AB = 30/√3
Now, Multiplying numerator and denominator by 3 we get:
AB = 30/√3 × √3/√3
AB = 30√3/3
AB = 10√3
Therefore, the height of the tower is 10√3.
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