the angle of elevation of the top of a tower from certain point is 30°. if the observer moves 20 meters towards the tower the angle of elevation of top of tower increased by 15° . find the height of tower
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Let the height of tower be h m
Now In triangle ABD, we have,
=h/x=tan45°=h/x=1 =h=x------(1)
Now In triangle ABC, we have,
h/x+20=tan30°
h/h+20=1/√3----(from 1 equation)
=√3h=h+20
=h(√3-1)=20
=h=20/(√3-1)
=h=20/(√3-1)×(√3+1)/(√3+1)
=h=10(√3+1) m
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