the angle of elevation of the top of a tower from certain point is 30. if the tower is 12 m tall find the distance of the point of observation from the foot if the tower.
Answers
Answered by
1
HEY FRND HERE IS YOUR ANSWER..
we have to find base of triangle ABC by using trigonometry....
PBP/HHB
tan 30 = perpendicular upon base
tan30 = AB/BC
1/√3=12/x
hence x=12√3m......
Hope you understand....
plz mark as brainlist...
we have to find base of triangle ABC by using trigonometry....
PBP/HHB
tan 30 = perpendicular upon base
tan30 = AB/BC
1/√3=12/x
hence x=12√3m......
Hope you understand....
plz mark as brainlist...
Attachments:
Answered by
4
Hii There!!!!
Please refer to the given attachment....
Here in the given question :
angle of elevation => θ = 30°
Height of the tower => AB = 12 m
Distance of the base => BC = ?
∵ tan θ = Perpendicular / Base => AB / BC
=> tan 30° = 12 / BC
=> 1 / √ 3 = 12 / BC
=> BC = 12 √ 3 m
______________________
# ¢' $ #
Hope it helps
Please refer to the given attachment....
Here in the given question :
angle of elevation => θ = 30°
Height of the tower => AB = 12 m
Distance of the base => BC = ?
∵ tan θ = Perpendicular / Base => AB / BC
=> tan 30° = 12 / BC
=> 1 / √ 3 = 12 / BC
=> BC = 12 √ 3 m
______________________
# ¢' $ #
Hope it helps
Attachments:
Similar questions