Question

The angle of elevation of the top of a tower from point on the ground which is 30metre away from the foot of the tower is 30degree.find the height of the tower

Answer 1

Answer:

Step-by-step explanation:

tan 30 = 1/√3

so, 1/√3 = ab/30

30 = √3ab

ab = 30/√3

multiplying √3 on numerator and denominator, we get

30√3/3=ab

10/√3 = ab

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Answer 2

Answer:

In ∆ ABC,

tan ∅ = Perpendicular/Height

tan 30° = AB/BC

1/√3 = AB/30

30/√3 = AB

AB = 30/√3

Now, Multiplying numerator and denominator by 3 we get:

AB = 30/√3 × √3/√3

AB = 30√3/3

AB = 10√3

Therefore, the height of the tower is 10√3.