Question

The angle of elevation of the top of a tower from the foot of a 5 m tall electric pole is 60° and angle of elevation of the top of the pole from the top of the tower is 30°. Find the height of the tower.

Answer 1

given:-

height of tower is H=30m and angle of elevation is 45°

then the distance between the foot of building and tower is given by-

AB=Htanθ ( θ=45°)

AB=30*1=30m

now the height of the building is given by-

h=ABtanθ ( θ=30°)

or h=30*1/√3

or h=10√3

Answer 2

Answer:

how come 45

please tell me now