Question

The angle of elevation of the top of a tower from two points p and q

Answer 1

Answer:

Let P be at distance a from the tower. This will make an angle %2890-alpha%29

Let height of tower be h

Tan%2890-alpha%29=h/a

Cot alpha=h/a

Tanalpha=a/h...

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Tan %28alpha%29 = h/b

a%2Fh=+h%2Fb

h%5E2=+ab

h=+sqrt%28ab%29

Answer 2

Step-by-step explanation:

AB is a tower. D and Care two points on the same side of a tower, BD = a and BC = b.

∠ADB and ∠ACB are the complementary angles.

If ∠ADB = x, then ∠ACB = 90 – x

In ∆ADB,

………… (1)

In ∆ABC,

…………....(2)

Multiplying (1) and (2),

(AB)2 = ab

AB = √ab

Height of tower = AB = √ab

Hence proved.

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