Question

the angle of elevation of the top of a tower from two points P and Q and distance of A and B respectively from the base and in the same straight line with the its compair complementary prove that the height of tower

Answer 1

PB=4m
QB=9m
alpha+beta=90

In triangle ABP,
tan alpha=AB/BP.............1


In triangle ABQ
tan beta=AB/BQ
tan(90-alpha)= AB/BQ
cot alpha= AB/BQ
1/tan alpha= AB/BQ
tan alpha=BQ/AB...........2



FROM 1 AND 2,
AB/BP=BQ/AB
AB*AB=BQ*BP
AB^2=4*9
AB^2=36
AB=6 M

Answer 2

Answer:

Check your answer please