The angle of elevation of the top of a tower from two points at a distance of 4m and 9m from the base of the tower and in the same straight line with it complementary. Prove that the height of the tower is 6m
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From fig, PB = 4m, QB = 9m. Let angle of elevation from P be α and angle of elevation from Q be β. Therefore, AB = 6. Hence, height of tower is 6m.
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Hence the height of tower is 6m..
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