The angle of elevation of the top of a tower height 100 mt from the point to its foot is tan inverse 4/5
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your complete question is ---> if the angle of elevation of the top of tower of height 100m from a point to its foot is tan inverse (4/5) then the distance from the point to its foot is
solution : A rough diagram is shown in figure. here α denotes the angle of elevation of tower at point P.
Let distance from point to foot of tower is x
given, height of tower = 100m
given, α = tan^-1(4/5)
now, using tanα = Perpendicular/base
or, tan{tan^-1(4/5)} = 100/x
or, 4/5 = 100/x
or, x = 100 × 5/4 = 125m
hence, distance from point to the foot of the tower is 125m.
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125m is the answer option a
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