Question

The angle of elevation of the top of a tower is 30°. If the height of the tower is doubled, then the angle of elevation of its top will​​

Answer 1

$\huge\blue{AnsweR:-}$

THEN THE ANGLE OF ELEVATION OF ITS TOP WILL BE LESS THAN 60°.

EXPLANATION:-

ACCORDING TO QUESTION.

$\tan30 \degree = \frac{h}{x}$

$= > \frac{1}{ \sqrt{3} } = \frac{h}{x}$

$= > h = \frac{x}{ \sqrt{3} }$

now, when height of tower is DOUBLED, we get:

$\tan \theta = \frac{2h}{x}$

$\tan\theta = \frac{2}{x} \times \frac{x}{ \sqrt{3} }$

$\tan\theta = \frac{2}{ \sqrt{3} }$

$\theta < 60 \degree$

hope it's clarify you ❤️

have a great day ❣️

Answer 2

Answer:

THEN THE ANGLE OF ELEVATION OF ITS TOP WILL BE LESS THAN 60°.

EXPLANATION:-

ACCORDING TO QUESTION.

\tan30 \degree = \frac{h}{x}tan30°=

x

h

= > \frac{1}{ \sqrt{3} } = \frac{h}{x}=>

3

1

=

x

h

= > h = \frac{x}{ \sqrt{3} }=>h=

3

x

now, when height of tower is DOUBLED, we get:

\tan \theta = \frac{2h}{x}tanθ=

x

2h

\tan\theta = \frac{2}{x} \times \frac{x}{ \sqrt{3} }tanθ=

x

2

×

3

x

\tan\theta = \frac{2}{ \sqrt{3} }tanθ=

3

2

\theta < 60 \degreeθ<60°