the angle of elevation of the top of a tower is 60°,at the distance of 50√3 from its base.find the height of the tower
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Let the height of the tower be h ;
then :
tan theta = Perpendicular/Base
tan 60° = h/50√3
√3 = h/50√3
h = 50√3 × √3
h = 50×3
h = 150 m
--------------–----
then :
tan theta = Perpendicular/Base
tan 60° = h/50√3
√3 = h/50√3
h = 50√3 × √3
h = 50×3
h = 150 m
--------------–----
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