Question

The angle of elevation of the top of a tower observed from each of the three points $A , B$ and $c$ on the ground forming a triangle is same angle $\bold{\alpha}$ . If $R$ is the cirumradius of triangle $ABC$ , then show that the height of the tower is $\bold{R tan \alpha}$.​

Answer 1

check attachment and mark as brainliest

Answer 2

Refer to the attachment .

α is the angle marked in the figure .

Let our radius be R .

A , B and C are the vertices of the triangle .

Let OH be the tower .

Hence we have to prove that OH = R tan α

In Δ OAH ,

tan α = height/base

⇒ tan α = OH/R

⇒ R tan α = OH

Hence the height of the tower is R tan α .

Hence proved !