Question

the angle of elevation of the top of a tower standing on a horizontal plane from a point a is, after walking a distance D towards the foot of the tower the angle of elevation is found to be beta the prove that the height of the tower is d/cotgamma-cot b
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Answer 1

Answer:

tanβ=xh    tanα=d+xh

∴x=tanβh

∴tanα=d+tanβhh

∴dtanα+tanβh.tanα=h

∴h=1−tanβtanαdtanα=tanβ−tanα.dtan.tanβ