The angle of elevation of the top of a tree from a point A on the ground is 60 degree on walking 20m away from its base to a point B the angle of elevation changes to 30 degree find the height of the tree
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Answer:
10√3 m.
Step-by-step explanation:
height of the tree = T
distance of tree from first position A = L
distance of tree from second position B = L + 20
T/L = tan 60 = √3 , L = T/√3
T/L +20 = tan 30 = 1/√3
T√3 = L + 20 = T/√3 +20
T(2/√3) = 20
T = 10√3 m.
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