Question

The angle of elevation of the top of a tree from a point at O distance of 200m from its base is 60 degrees. The height of the tree is.​

Answer 1

Given :

Distance of the point O from the base = 200 m

Angle of elevation = 60°

To find :

The height of the tree .

Solution :

tanθ = height / base

Now ,

( height of the tree ) / ( Distance of the point O from the base ) = tan 60°

=> ( height of the tree ) / 200 = √3

=> height of the tree = 200√3 m

The height of the tree is 200√3 m .

Answer 2

Step-by-step explanation:

Given that: The angle of elevation of the top of a tree from a point at O distance of 200m from its base is 60 degrees.

To find: The height of the tree ?

Solution: To understand the given situation first draw it.

From attachment one can easily understand that

AB=To find

AC= 200 m

Angle of elevation= 60°

We know that for ratio of sides Perpendicular to base , trigonometry function tan is used

$tan \theta = \frac{AB}{AC} \\ \\ tan \: 60° = \frac{AB}{200} \\ \\ \sqrt{3} = \frac{AB}{200} \\ \\ \bold{\green{AB = 200 \sqrt{3} \: m}}$

Thus,height of tree is 200√3 m.

Hope it helps you.