Question

The angle of elevation of the top of a tree height 200√3 m at a point

at distance of 200m from the base of the tree is ____​

Answer 1

hope this will help you.

Answer 2

Answer:

Step-by-step explanation:

Given Height of tree = 200$\sqrt{3}$m

Distance between from a point of observation and foot of the tree is 200 m

angle of elvation to top of tree is  Tan Ф =opp/adj

Tan Ф =200√3/200

tanФ =$\sqrt{3}$

tanΘ = tan60

Ф = 60