The angle of elevation of the top of a tv tower from three points a,b and c in a straight line through the foot of the tower are α,2α and 3α,α,2α and 3α, respectively. If ab=a,ab=a, then height of the tower is
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Answer:
Step-by-step explanation:
Let OP be the height
Open the vertical pole for Tower
Given the angles as Alpha 2 Alpha and 3 Alpha respectively.
Δd =OBP, OP/BP=sin2α
So OP=BPsin2α=asin2α
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