Math, asked by kochupurackal8, 1 year ago

The angle of elevation of the top of a vertical tower from a point on the ground is 60 degree. From another point 10m vertically above the first, its angle of elevation is 45 degree. Find the height of the tower.


niti09: 5(√3+1)

Answers

Answered by Vanshika08112003
2
Your answer is in attachment




hope this helps you
Attachments:
Answered by swaymeda
0

Answer: 5(√3 + 1)

Step-by-step explanation:

Let ED = x, AD = BC = y, AB = DC = 10m, tanA = 45°, tan B = 60°.

Triangle EAD,

tan 45° = ED/AD

1 = x/y

x = y.......... (1)

Triangle EBC,

tan 60° = ED + DC / BC

√3 = x + 10 / y

From (1),

√3 = x +10 / x

√3x - x = 10

x (√3 - 1) = 10

x = 10 / √3 - 1

x = 10 (√3 + 1 ) / 2

x = 5(√3 + 1 )

(√3 = 1.732)

Therefore, ED = x = 11.470m

Total height = ED + CD = 11.470 + 10 = 21.470mts

Similar questions