The angle of elevation of the top of a vertical tower from a point on the ground is 60 degree. From another point 10m vertically above the first, its angle of elevation is 45 degree. Find the height of the tower.
niti09:
5(√3+1)
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Answer: 5(√3 + 1)
Step-by-step explanation:
Let ED = x, AD = BC = y, AB = DC = 10m, tanA = 45°, tan B = 60°.
Triangle EAD,
tan 45° = ED/AD
1 = x/y
x = y.......... (1)
Triangle EBC,
tan 60° = ED + DC / BC
√3 = x + 10 / y
From (1),
√3 = x +10 / x
√3x - x = 10
x (√3 - 1) = 10
x = 10 / √3 - 1
x = 10 (√3 + 1 ) / 2
x = 5(√3 + 1 )
(√3 = 1.732)
Therefore, ED = x = 11.470m
Total height = ED + CD = 11.470 + 10 = 21.470mts
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