the angle of elevation of the top of a vertical Tower from a point on the ground is 60 . from another point 10m vertically above the first
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let height of tower = x + 10m
let dist. between base of tower and obs. pt. = y
at first angle it makes with ground = 60 degree
tan(60) = sqrt{3} = (x + 10)/y . . . . . . (eq 1)
next angle = 45 degree
pt is 10 m above the ground
tan(45)= 1 = x/y
:. x=y . . . . . . . . . (eq. 2)
substituting value of y in eq. 1
x + 10 = 1.732 x
:. x = 13.66
let dist. between base of tower and obs. pt. = y
at first angle it makes with ground = 60 degree
tan(60) = sqrt{3} = (x + 10)/y . . . . . . (eq 1)
next angle = 45 degree
pt is 10 m above the ground
tan(45)= 1 = x/y
:. x=y . . . . . . . . . (eq. 2)
substituting value of y in eq. 1
x + 10 = 1.732 x
:. x = 13.66
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