Question

The angle of elevation of the top of a vertical tower on a level ground from point, at a distance of 9√3 m from its foot on the same ground is 60°. Find the height of the tower​

Answer 1

The height of the tower, which is 9√3 m away from the same point on the ground that subtends an angle of elevation of 60° to the top of the tower, is 27 m.

Step-by-step explanation:

Referring to the figure, let's make some assumptions,

h = AB = height of the tower

θ = 60° = angle of elevation of the top of the tower from the point C

BC = 9√3 m = the distance of the foot of the tower from point C

Now, Considering the right triangle ABC and applying the trigonometric ratios of a triangle, we get

tan θ = Perpendicular / Base

⇒ tan 60° = AB/BC

⇒ √3 = h / 9√3

⇒ h = 9√3 * √3

⇒ h = 9 * 3  

⇒ h = 27 m

Thus, the height of the tower is 27 m.

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Answer 2

Answer:

Step-by-step explanation: