Question

the angle of elevation of the top of an unfinished vertical building on a ground at a point which is 100 M from the base of the building is 45 degree how much weight the building must be resized so that its angle of elevation from same point be 60 take root 3 is equal to 1.73​

Answer 1

Answer:

$h = 173m$

Step-by-step explanation:

IN TRIANGLE DBC

$\tan(45) = \frac{db}{bc} \\ 1 = \frac{h}{100} \\ h = 100$

IN TRIANGLE ABC

$tan(60) = \frac{ab}{bc} \\ \sqrt{3} = \frac{h + x}{100} \\ \sqrt{3} = \frac{100 + x}{100} \\ 100 \sqrt{3} = 100 + x \\ x = 100 \sqrt{3} - 100 \\ x = 100( \sqrt{3} - 1) \\ x =100 (1.73 - 1) \\ x = 100 \times 0.73 \\ x = 73 \\ the \: height \: of \: the \: building \: which \: is \: resized = h + x \\ = 100 + 73 \\ = 173m$

Answer 2

Answer:

73m

Step-by-step explanation:

Refer the picture