Math, asked by sudhapavi9141, 11 months ago

the angle of elevation of the top of an unfinished verticle building on a ground, at a point which is 100m from the base of the building is 45 degree. How much height the building be raised, so that its angle of elevation from the same point be 60 degree. (Take root3 =1.73)​

Answers

Answered by noorulhaque8979
14

the building to be raised is 73 metre

then the total height of the building becomes 173metre

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Answered by lublana
5

The height of building raised by 73 m when the angle of elevation from the same point is 60 degree.

Step-by-step explanation:

CD=100 m

In triangle BCD

\theta=45^{\circ}

\frac{BC}{CD}=tan45

Using

\frac{Perpendicular\;side}{Base}=tan\theta

\frac{BC}{100}=1

BC=100 m

AC=AB+BC=AB+100

In triangle ACD

\theta=60^{\circ}

\frac{AC}{CD}=tan60

\frac{AB+100}{100}=\sqrt 3

Using tan60^{\circ}=\sqrt 3

AB+100=100\times 1.73=173

Using \sqrt 3=1.73

AB=173-100=73 m

Hence, the height of building raised by 73 m when the angle of elevation from the same point is 60 degree.

#Learns more:

https://brainly.in/question/14572325:Answered by Tanikawaddle

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