Question

The angle of elevation of the top of building 30m high from the foot of another building in the same plane is 60(degree)and also angle of elevation of top of second building from foot of first building is 30(degree) then distance between 2 buildings __________. ​

Answer 1

$\huge\fbox{\dag Answer \dag}$

Let h= height of second tower, d=distance between two towers

height of first tower = 30 m

From given data,

$\frac{30}{d}$=tan60°=√3

$\frac{h}{d}$=tan30°=$\frac{1}{√3}$

√3h=d,30=d√3

h=10m,d=10√3m

Therefore, height of the other tower is 10 m.

Answer 2

Answer:

here is your answer..

Step-by-step explanation:

ANSWER

Let h= height of second tower, d=distance between two towers

height of first tower = 30 m

From given data,

d

30

=tan60

∘

=

3

d

h

=tan30

∘

=

3

1

3

h=d,30=d

3

h=10 m, d=10

3

m

Therefore, height of the other tower is 10 m.