Question

the angle of elevation of the top of minarand angle of depression of the foot of Minar at the top of a 7m high building are 60 degree and 30 degree respectively find the height of minar​

Answer 1

Answer:

in case of 30degree

anngle of depression = 30degree

height/base=tan30

7/base=1/√3

base=7√3m

now in case of 60 degree angle of elevation

let hight be h then

height/ base=tan60

h/7√3=√3

h=21m

now height of minar=7+21=28m

Answer 2

The height of minar=28 m

Step-by-step explanation:

Height of building=7m

ABCD is a rectangle

AB=CD=7m

BC=AD

In triangle ABC

$tan\theta=\frac{perpendicular\;side}{base}$

Substitute the values then we get

$tan30=\frac{7}{BC}$

$\frac{1}{\sqrt 3}=\frac{7}{BC}$

$BC=7\sqrt3 =AD$

In triangle EDA

$tan60=\frac{ED}{AD}$

Substitute the values then we get

$\sqrt 3=\frac{ED}{7\sqrt 3}$

$ED=\sqrt 3\times 7\sqrt 3}=21 m$

Height of minar=ED+DC=21+7=28 m

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